• IDÀúÀåȸ¿ø°¡ÀÔIDÆнº¿öµåã±â
  • :: ¼±¼ö°Ë»ö

°øÁö»çÇ×

Ȩ°Ô½ÃÆÇ°øÁö»çÇ×

±Ûº¸±â
Á¦¸ñ 12¿ù 17/18ÀÏ °æ±âÀüÀû
ÀÛ¼ºÀÚ »ç¹«±¹ Á¶È¸ 1626
ÀÛ¼ºÀÏ 2011.12.18 ¿ÀÈÄ 10:37:18
÷ºÎÆÄÀÏ
[ÆòÀϳªÀÌÆ®¸®±×Èıâ]
´ºÅ¬¸®¾î½º2 13:18 ´ë±¸¶óÀÌ¿ÂÁî
(3½Â12ÆÐ) (9½Â5ÆÐ)
°í½ºÆ®2 7:16 J.BEE½ºÆ÷Ã÷
(4½Â10ÆÐ) (13½Â5ÆÐ)
KD´ºÅ¬¸®¾î 13:14 ·¹Àκ¸¿ì
(16ÆÐ) (8½Â8ÆÐ)
´ºÅ¬¸®¾î½º2 7:9 °í½ºÆ®2
(3½Â13ÆÐ) (5½Â10ÆÐ)
KD´ºÅ¬¸®¾î 5:31 ´ë±¸¶óÀÌ¿ÂÁî
(17ÆÐ) (10½Â5ÆÐ)
³ªÀÌÆ®º£¾î½º 12:2 ½ºÄ«À̸ðÅͽº
(13½Â5ÆÐ) (12½Â5ÆÐ)

[´ÙÀ̾Ƹóµå¸®±×]
¿Â´©¸® 7:0 ÇÇÇÃÁî
(2½Â11ÆÐ) (5½Â8ÆÐ)

[ÆòÀϼ­¶ó¹ú¸®±× Ç÷¹ÀÌ¿ÀÇÁ 3,4À§Àü]
¹ß·» ŸÀÎ 2 1 1 2 1 =7
C-Æйи®B 0 4 2 7 x =13

[°ø¹«¿ø1¸®±× Ç÷¹ÀÌ¿ÀÇÁ °á½Â1Â÷Àü]
´ë±¸µµ½Ãöµµ 5 0 0 2 1 0 1 =9
´ë±¸½Ã±³À°Ã» 1 0 1 1 0 2 2 =7

[°ø¹«¿ø2¸®±× Ç÷¹ÀÌ¿ÀÇÁ°á½ÂÀü]
GB ÇÏÀÌÆнº 0 0 0 1 0 1 0 =2
K N U 3 3 0 2 1 0 x =9 (¿ì½ÂÈ®Á¤)

[¹ÙÀÌºí¸®±× Ç÷¹ÀÌ¿ÀÇÁ 4°­Àü]
Á¦ÀϿ丮Á¶¸® 1 1 4 1 3 0 =10
ħ»êµ¿ºÎ±³È¸ 0 0 0 0 1 0 =1

[û¼Ò³â¸®±× Ç÷¹ÀÌ¿ÀÇÁ °á½ÂÀü]
ÿ ¸° Á® 3 0 0 0 0 0 0 =3
Ä«µð³Î½º 1 2 0 2 0 2 x =7 (¿ì½ÂÈ®Á¤)

[Æ÷½ºÆ®¸®±× Ç÷¹ÀÌ¿ÀÇÁ °á½ÂÀü]
´Þ¼­½º¿Ð·ÎÁî 0 1 0 2 0 0 1 =4
¼ö¼º ¿ìü±¹ 0 1 9 1 2 2 x =15 (¿ì½ÂÈ®Á¤)

[ÇѶ󸮱×]
½´ÆۼҴнº (8½Â3ÆÐ) 1:0 ´ëÁøâȣ (7½Â4ÆÐ)
ºí·ç¹öµå (8½Â1¹«2ÆÐ) 5:2 µ¿Çàºê¶ó´õ½º (8½Â3ÆÐ)

[Źé2¸®±×]
»ó½Åºê·¹ÀÌÅ© (6½Â1¹«5ÆÐ) 16:13 ¹ß·»Å¸ÀÎ (6½Â1¹«6ÆÐ)
»ïÀÍ·¹Àüµå (4½Â8ÆÐ) 11:9 »ó½Åºê·¹ÀÌÅ© (6½Â1¹«6ÆÐ)
´ë±¸ºÒ½º (8½Â1¹«4ÆÐ) 14:13 »ïº¸ÇǴнº (8½Â5ÆÐ)
ÅÊÅ©A (5½Â7ÆÐ) 0:7 Çѱ¹°ÔÀÌÃ÷ (7½Â6ÆÐ)
µå¸²¾î½º (9½Â4ÆÐ) 7:0 ÅÊÅ©A (5½Â8ÆÐ)
ÆÀ³ªÀÎ (2½Â10ÆÐ) 5:9 SDÆÄÀ̾Ã÷ (8½Â5ÆÐ)

[ÆÈ°ø¸®±×]
È­ÀÌÆ®º£¾î (4½Â2¹«7ÆÐ) 10:18 ¹ÂÁö¼Ç (8½Â1¹«4ÆÐ)
¿£Á©½º (5½Â2¹«5ÆÐ) 10:10 ºòº¼ (6½Â2¹«5ÆÐ)
¿£Á©½º (5½Â2¹«6ÆÐ) 3:4 ¾Æ½Î¶óºñ¾ß (7½Â2¹«4ÆÐ)

[Åä¿äµå¸²¸®±× Ç÷¹ÀÌ¿ÀÇÁ 3,4À§Àü]
È÷Åͽº 15-6 G¼îÅ©

[Åä¿ä¸ÅÁ÷¸®±× Ç÷¹ÀÌ¿ÀÇÁ °á½ÂÀü]
´ë±¸¼ö¼º J C 0 3 1 0 3 3 0 =10 (¿ì½ÂÈ®Á¤)
ºÏºÎ¸Å¸Å´ÜÁö 0 3 1 2 0 0 0 =6

[Åä¿ä·çÅ°¸®±× Ç÷¹ÀÌ¿ÀÇÁ 6°­Àü]
´ë¼º±Û·Î¹ú 1 1 2 4 0 2 5 =15
ÇØÅÂÆйи® 2 12 0 0 2 0 =16

ÄÚ ¸® ¾Æ ³ª 1 1 1 1 1 0 3 =8
ÇÔ²²Çϴ¸¶À½Àç´Ü 2 0 2 4 0 0 1 =9

[·çÅ°1-B¸®±× Ç÷¹ÀÌ¿ÀÇÁ 4°­Àü]
Ä«¸®½º¸¶ 1 0 0 0 1 =2
Á¶¸í¹ðÅ© 3 8 0 0 1 =12

[ºñ±â³Ê2-B¸®±× Ç÷¹ÀÌ¿ÀÇÁ 6°­Àü]
SMÆÄÀÌÅÍÁî 1 0 0 1 1 0 =3
·¹µåºñ½º B 5 0 1 0 1 4 =11

¸¶ ´Ï Ä¿ 5 7 1 3 1 0 =17
SB¹èµå°¡ÀÌÁî 0 3 0 0 8 X =11

[·çÅ°1-A¸®±× Ç÷¹ÀÌ¿ÀÇÁ 4°­Àü]
¹Ì¸£ ³ªÀÎ 0 3 2 0 0 2 3 =10
·¹µåºñ½ºA 0 3 0 0 1 3 4 =11 (·¹µåºñ½ºA ½ÂºÎÄ¡±â ½Â)

´ë±¸¾Æ½½¾Æ½½ 1 0 0 3 2 1 =7
¶ó ²Ù ¿£ 0 5 0 2 0 5 =12
ÀÌÀü±Û ¸®±×°¡ÀÔºñ ¾È³»
´ÙÀ½±Û Æ÷½ºÆ®¸®±× Ç÷¹ÀÌ¿ÀÇÁ °á°ú Áý°è